趣味的数学-192

作者:gugeren
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趣味的数学-192


a、b、c和d是正整数,有a^5 = b^4,c^3 = d^2,c - a = 19。

求 d - b。


  • 当前共有1条跟帖
  • 零加一中:d - b = 757

    a = m^4

    c = n^2

    19 = c - a = (n + m^2)(n - m^2)

    Since 19 is prime, n + m^2 = 19 and n - m^2 = 1.

    n = 10 and m = 3

    c = 100 and a = 81

    d = 1000 and b = 243

    d - b = 757

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    zhf 回复 零加一中:得到同样结果
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    gugeren 回复 zhf:是
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